Question

How do I find the value of sin 105?

Answer 1

It is `sin105^o=1/4*(sqrt6+sqrt2)`

Explanation:

We have that

`sin(105)=sin(60+45)`

because

`sin(a+b)=sina*cosb+cosa*sinb`

hence, we have

#sin105=sin(60+45)=sin60*cos45+cos60*sin45= =sqrt3/2*sqrt2/2+1/2*sqrt2/2=1/4(sqrt6+sqrt2)#