Question

How do I find the value of sin (pi/12)?

Answer 1

`sin(pi/12)=sqrt2/4*(sqrt3-1)`

Explanation:

It is

`sin(pi/12)=sin(pi/3-pi/4)=sin(pi/3)*cos(pi/4)-cos(pi/3)*sin(pi/4)=>sin(pi/12)=sqrt3/2*sqrt2/2-1/2*sqrt2/2=sqrt2/4*(sqrt3-1)`