How do I find the vertex of #y=(x+2)^2-3#?

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Answer 1 · 2015-07-29T19:54:06

The vertex is at #color(red)((-2,-3)#.

#y = (x +2)^2-3#

The vertex form for the equation of a parabola is

#y = a(x-h)^2 + k#, where (#h, k#) is the vertex of the parabola.

Your equation is already in vertex form

By comparing the two equations, we see that #h = -2# and #k = -3#.

The vertex is at (#-2,-3#).

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