# How do I find the x-intercepts for the graph of y=x^2-3x-4?

Jul 9, 2015

You set $y = 0$ and solve for $x$.

#### Explanation:

y = x^2–3x-4 = 0

$\left(x + 1\right) \left(x - 4\right) = 0$

$x + 1 = 0 \mathmr{and} x - 4 = 0$

$x = - 1$ or $x = 4$

The $x$-intercepts are at ($- 1 , 0$) and ($4 , 0$).