How do I find the x-intercepts of a parabola?

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Answer 1 · 2014-10-25T17:20:35

Since the equation for a parabola describe a quadratic function

#y=ax^2+bx+c#,

where #a#, #b#, and #c# are any real numbers such that #a ne 0#,

we can find the x-intercepts by solving the quadratic equation

#ax^2+bx+c=0#.

One way to do that, we can use the quadratic formula

#x={-b pm sqrt{b^2-4ac}}/{2a}#.

I hope that this was helpful.