How do I simplify this expression? sin^2x-cos^2x/sinx-cosx

1 Answer
Mar 18, 2018

sinx+cosx

Explanation:

(sin^2x-cos^2x)/(sinx-cosx)=

Since the numerator has a difference of squares:
(a^2-b^2) = (a+b)*(a-b)

((sinx-cosx)(sinx+cosx))/(sinx-cosx)=

((cancel(sinx-cosx))(sinx+cosx))/cancel(sinx-cosx)=

sinx+cosx