#cos(-60^0)#.
first convert #60^0# in radians just for the sake of convenience of problem solving in trigonometry. since #pi# radian =#180^0##rArr 60^0=(pi/3) radians#
now, since #cos(-theta)=costheta# ,
so, #cos(-pi/3)=cos(pi/3)=1/2# (a standard value and should be memorised)