How do I use elimination to find the solution of the system of equations 3x+4y=10 and x−y=1?

Apr 22, 2018

$x = 2 , y = 1$

Explanation:

$3 x + 4 y = 10 - - \left(1\right)$

$x - y = 1 - - - \left(2\right)$

$\left(2\right) \times 4$

$4 x - 4 y = 4 - - - \left(2 a\right)$

$3 x + 4 y = 10 - - - \left(1\right)$

$\left(2 a\right) + \left(1\right)$

$7 x = 14 \implies x = 2$

subs into$\left(2\right)$

2-y=1#

$\therefore y = 1$

quick mental check in $\left(1\right)$ confirms trhe solns