# How do you solve the system 3x+2y =3, 2x+0y = -5?

Nov 15, 2015

$x = - \frac{5}{2}$
$y = \frac{21}{4}$

#### Explanation:

We can already get the value of $x$ in the second equation.

$2 x + 0 y = - 5$

$\implies 2 x = - 5$

$\implies x = - \frac{5}{2}$

Now, to get the value of $y$, we plug-in the value of $x$ in the first equation

$3 x + 2 y = 3$

$\implies 3 \left(- \frac{5}{2}\right) + 2 y = 3$

$\implies - \frac{15}{2} + 2 y = 3$

$\implies 2 y = 3 + \frac{15}{2}$

$\implies 2 y = \frac{6 + 15}{2}$

$\implies 2 y = \frac{21}{2}$

$\implies y = \frac{21}{4}$