How do I use the quadratic formula to solve #f(x) = 4x^2 + 12x + 9#?

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Answer 1 · 2014-09-30T03:19:58

#ax^2+bx+c=0#

#4x^2+12x+9=0#

#a=4, b=12, c=9#

Quadratic formula

#x=(-(12)+-sqrt((12)^2-4(4)(9)))/(2(4))#

#x=(-12+-sqrt(144-144))/8#

#x=(-12+-sqrt(0))/8#

#x=(-12)/8#

#x=-3/2#

#x=-1.5#