How do solve the following linear system?: x/2 - y/4 = -1 , x/3-2y=2 ?

1 Answer
Jan 2, 2016

x=-30/11, y=-16/11

Explanation:

By substitution method

x/2-y/4=-1 ---(1)

Multiply equation (1) by 2:

x-y/2=-2

x=y/2-2 ---(2)

x/3-2y=2 ---(3)

Substitute equation (2) into equation (3)

1/3(y/2-2)-2y=2

y/6-2/3-2y=2

-11/6y=2/3+2

-11/6y=8/3

y=-16/11

Substitute y=-16/11 into equation (2)

x=-8/11-2

x=-30/11

Thus, x=-30/11, y=-16/11