How do solve the following linear system?: $x - 3y = 8 , 8x+2y=2$ ?

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Answer 1 · 2017-05-13T14:10:06

$x=11/13,y=-(31/13)$

We can solve this using elimination of variables. We can multiply $x-3y=8$ by $8$ to get $8x-24y=64$ . We can then subtract the two equations:

$(8x+2y=2)-(8x-24y=64) => 26y=-62$

Dividing both sides of the equation by 26, we get:

$y=-(62/26) =>y = -(31/13)$

Substituting the value of $y$ into the first equation, we get:

$x-3(-(31/13))=8=>x+93/13=8$

$x=8-93/13=>x=104/13-93/13$

$x=11/13$

How do solve the following linear system?: x - 3y = 8 , 8x+2y=2 x - 3y = 8 , 8x+2y=2 ?