# How do you add 5sqrt48-4sqrt75?

Apr 26, 2018

$5 \sqrt{48} - 4 \sqrt{75} = 0$

#### Explanation:

First, attempt to simplify the radicals.

$5 \sqrt{48} - 4 \sqrt{75}$

$5 \sqrt{6 \times 8} - 4 \sqrt{15 \times 5}$

$5 \sqrt{{2}^{4} \times 3} - 4 \sqrt{3 \times {5}^{2}}$

The squares can be factored out.

$5 \times {2}^{2} \sqrt{3} - 5 \times 4 \sqrt{3}$

This can now be simplified:

$\left(5 \times {2}^{2} - 5 \times 4\right) \times \sqrt{3}$

$\left(20 - 20\right) \times \sqrt{3}$

$\left(0\right) \times \sqrt{3} = 0$