Question

How do you add or subtract `(t^2 + 6t)/(t-1) – (7)/(t – 1)`?

Answer 1

Assuming `t!=1`

`(t^2+6t)/(t-1) - 7/(t-1)`

Since both terms have a common denominator the expression can be re-written as
`(t^2+6t -7)/(t-1)`

Factoring the numerator:
`= ((t-1)(t+7))/(t-1)`

`= t+7`