# How do you add (x^2 + 3x+5) + (x^2 + 4x + 1) ?

Sep 9, 2015

$\left({x}^{2} + 3 x + 5\right) + \left({x}^{2} + 4 x + 1\right)$
$\textcolor{w h i t e}{\text{XXX}} = 2 {x}^{2} + 7 x + 6$

#### Explanation:

Well you can do it like this
$\left(\textcolor{red}{{x}^{2}} + \textcolor{red}{3 x} + \textcolor{red}{5}\right) + \left(\textcolor{b l u e}{{x}^{2}} + \textcolor{b l u e}{4 x} + \textcolor{b l u e}{1}\right)$

$\textcolor{w h i t e}{\text{XXX}} = \left(\textcolor{red}{{x}^{2}} + \textcolor{b l u e}{{x}^{2}}\right) + \left(\textcolor{red}{3 x} + \textcolor{b l u e}{4 x}\right) + \left(\textcolor{red}{5} + \textcolor{b l u e}{1}\right)$

$\textcolor{w h i t e}{\text{XXX}} = 2 {x}^{2} + 7 x + 6$