# How do you add (z -8/3) + (4/3z^2 -z +1?

Only terms containing $z$ to the same exponent can be combined.
$\left(z - \frac{8}{3}\right) + \left(\frac{4}{3} {z}^{2} - z + 1\right)$
$\textcolor{g r e e n}{\frac{4}{3} {z}^{2}} + \textcolor{red}{z - z} + \textcolor{b l u e}{\left(- \frac{8}{3}\right) + 1}$
$= \frac{4}{3} {z}^{2} - \frac{5}{3}$
$= \frac{4 {z}^{2} - 5}{3}$