How do you balance #AlBr_3 + K_2SO_4 -> KBr + Al_2(SO_4)_3#?

Question

2076 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-18T09:54:04

#2AlBr_3 + 3K_2SO_4 rarr 6KBr + Al_2(SO_4)_3#

To balance this equation, all you have to do is make sure that there is an equal number of each element in both the reactant and product side.

Step by step balancing:

#AlBr_3 + K_2SO_4 -> KBr + Al_2(SO_4)_3# (unbalanced)

reactants:
Al - 1 Br - 3 K - 2 S - 1 O - 4
products:
Al - 2 Br - 1 K - 1 S - 3 O - 12

#AlBr_3 + 3K_2SO_4 -> KBr + Al_2(SO_4)_3# (unbalanced)

reactants:
Al - 1 Br - 3 K - 6 S - 3 O - 12
products:
Al - 2 Br - 1 K - 1 S - 3 O - 12

#2AlBr_3 + 3K_2SO_4 -> KBr + Al_2(SO_4)_3# (unbalanced)

reactants:
Al - 2 Br - 6 K - 6 S - 3 O - 12
products:
Al - 2 Br - 1 K - 1 S - 3 O - 12

#2AlBr_3 + 3K_2SO_4 -> 6KBr + Al_2(SO_4)_3# (balanced)

reactants:
Al - 2 Br - 6 K - 6 S - 3 O - 12
products:
Al - 2 Br - 6 K - 6 S - 3 O - 12