How do you balance #AlBr_3 + K_2SO_4 -> KBr + Al_2(SO_4)_3#?

1 Answer
Jan 18, 2016

Answer:

#2AlBr_3 + 3K_2SO_4 rarr 6KBr + Al_2(SO_4)_3#

Explanation:

To balance this equation, all you have to do is make sure that there is an equal number of each element in both the reactant and product side.

Step by step balancing:

#AlBr_3 + K_2SO_4 -> KBr + Al_2(SO_4)_3# (unbalanced)

reactants:
Al - 1 Br - 3 K - 2 S - 1 O - 4
products:
Al - 2 Br - 1 K - 1 S - 3 O - 12

#AlBr_3 + 3K_2SO_4 -> KBr + Al_2(SO_4)_3# (unbalanced)

reactants:
Al - 1 Br - 3 K - 6 S - 3 O - 12
products:
Al - 2 Br - 1 K - 1 S - 3 O - 12

#2AlBr_3 + 3K_2SO_4 -> KBr + Al_2(SO_4)_3# (unbalanced)

reactants:
Al - 2 Br - 6 K - 6 S - 3 O - 12
products:
Al - 2 Br - 1 K - 1 S - 3 O - 12

#2AlBr_3 + 3K_2SO_4 -> 6KBr + Al_2(SO_4)_3# (balanced)

reactants:
Al - 2 Br - 6 K - 6 S - 3 O - 12
products:
Al - 2 Br - 6 K - 6 S - 3 O - 12