# How do you balance C_10H_16 + Cl_2 -> C + HCl?

Jun 2, 2016

C_10H_16 + 8 Cl_2 →10 C + 16 HCl
Balance the carbon first by putting a coefficient of 10 in front of the C on the products side. Afterwards, balance the H by putting a coefficient of 16 in front of the HCl molecule. Now, the only thing that's not balanced is chlorine. So just place a coefficient of 8 in front of the $C {l}_{2}$ molecule, since you obtain 16 when the subscript is multiplied by the coefficient.