# How do you balance C_3H_8 + O_2 -> CO_2 + H_2O?

Mar 1, 2016

#### Answer:

If you mean complete combustion of propane:

${C}_{3} {H}_{8} \left(g\right) + 5 {O}_{2} \left(g\right) \rightarrow 3 C {O}_{2} \left(g\right) + 4 {H}_{2} O \left(l\right)$

#### Explanation:

Garbage in must equal garbage out. Complete combustion specifies that all of the carbon reactant is oxidized to $C {O}_{2}$.

To make sure that it is balanced look at the left hand sides and right sides: LHS: $3 \times C + 8 \times H + 10 \times O$; RHS: $3 \times C + 8 \times H + 10 \times O$. Reactants and products are stoichiometrically balanced as they must be.

Can you represent the complete combustions of pentane, ${C}_{5} {H}_{12}$, and then hexane, ${C}_{6} {H}_{14}$?