How do you balance #CuCl_2 + Fe -> 2Cu + FeCl_2#?

1 Answer
Apr 21, 2018

Answer:

Like this:

Explanation:

I'd start by looking at what is the most complicated and unbalanced, as we can see there is only 1 #Cu# on the left hand side but there is two #Cu# on the right side.
So add a 2 in front of #CuCl_2#

#2CuCl_2 + Fe ->2Cu+FeCl_2#

But now Chlorine is unbalanced on the left side, as we have 4 on the right, so add a 2 in front of #FeCl_2#

#2CuCl_2 + Fe ->2Cu+2FeCl_2#

Finally balance for iron as that is the only thing left by adding a 2:

#2CuCl_2 +2 Fe ->2Cu+2FeCl_2#

And now it is balanced!