How do you balance Fe(s) + S(s) -> Fe_2S_3(s)?

Feb 22, 2017

$2 F {e}_{s}$ + $3 {S}_{s}$ ------------> $F {e}_{2} {S}_{3}$

Explanation:

Step 1 : First of all write the equation
$F {e}_{s}$ + ${S}_{s}$ ------------> $F {e}_{2} {S}_{3}$

Step 2 : Now balance the number of $F e$ atoms on both reactant and product side

Here reactant side has one $F {e}_{S}$ atom and product side has $2$ atoms of $F {e}_{S}$, therefore multiply $F {e}_{S}$ at reactant side by $2$

Step 3: Balance ${S}_{s}$

Here reactant side has one ${S}_{s}$ atom and product side has $3$ atoms of ${S}_{s}$, therefore multiply ${S}_{s}$ at reactant side by $3$

Step 4.
Write the final eqaution

$2 F {e}_{s}$ + $3 {S}_{s}$ ------------> $F {e}_{2} {S}_{3}$