# How do you balance H_2SO_4 + NH_4OH -> H_2O + (NH_4)_2SO_4?

Jun 2, 2016

The balanced equation is
${H}_{2} S {O}_{4} + 2 N {H}_{4} O H \to 2 {H}_{2} O + {\left(N {H}_{4}\right)}_{2} S {O}_{4}$

#### Explanation:

This is a neutralization equation of an acid ${H}_{2} S {O}_{4}$, sulfuric acid with a base $N {H}_{4} O H$ ammonium hydroxide to form water ${H}_{2} O$ and a salt ${\left(N {H}_{4}\right)}_{2} S {O}_{4}$ ammonium sulfate.

When balancing a neutralization, balance the water ${H}_{2} O$ is $H O H$ and the rest of the equation will balance.

${H}_{2} S {O}_{4} + N {H}_{4} O H \to {H}_{2} O + {\left(N {H}_{4}\right)}_{2} S {O}_{4}$

The 2 ${H}^{+}$ ions in the acid need 2 $O {H}^{-}$ ions to form 2 water molecules $H O H$ or ${H}_{2} O$

Therefore the equation balances at

${H}_{2} S {O}_{4} + 2 N {H}_{4} O H \to 2 {H}_{2} O + {\left(N {H}_{4}\right)}_{2} S {O}_{4}$