# How do you balance HBr + Mg(OH)_2 -> MgBr_2 + H_2O?

Apr 1, 2016

i will tell u the steps.

#### Explanation:

Let the equation be

a $H B r$ + b $M g {\left(O H\right)}_{2}$ $\to$ c $M g B {r}_{2} + d {H}_{2} O$

Equating $H$-atoms on both sides,

a+2b=2d

Equating $B r$ on both sides,

a=2c

Equating $M g$ on both sides,

b=c

Equating $O$ on both sides,

2b=d

So..........a+2b=2d
$\Rightarrow$ 2c+2(c)=2d
$\Rightarrow$ 4c=2d
$\Rightarrow$ d=2c

Finally, substituting a,b,c,d

2c $H B r$ + c $M g {\left(O H\right)}_{2}$ $\to$ c $M g B {r}_{2}$ + 2c ${H}_{2} O$

2 $H B r$ + $M g {\left(O H\right)}_{2}$ $\to$ $M g B {r}_{2}$ + 2 ${H}_{2} O$