# How do you balance Na + MgF_2 -> NaF + Mg?

Dec 7, 2015

$2 N a + M g {F}_{2} \rightarrow 2 N a F + M g$

#### Explanation:

The $2$ F's on the left side ($M g {F}_{\textcolor{red}{2}}$) imply the that right side must have $2$ F's (or a multiple of $2$).

The only F on the right side is in NaF
so to have $2$ F's on the right side we will need $2$ NaF's.
$\textcolor{w h i t e}{\text{XXX}} \textcolor{red}{2 N a F} + M g$

This gives us $2$ Na's on the right side ($\textcolor{b l u e}{2 N a} F$)
which implies we will need $2$ Na's on the left side.
$\textcolor{w h i t e}{\text{XXX}} \textcolor{b l u e}{2} N a + M g {F}_{2} \rightarrow \textcolor{b l u e}{2 N a} F + M g$

At this point the transformation becomes balanced:
On both sides we have:

$2 N a$'s
$1 M g$, and
$2 F$'s