How do you balance #NH_3 + H_2SO_4 -> (NH_4)_2SO_4#?
The balanced equation is the following:
First start by looking at the sulfate group
Second, we have two nitrogen atoms in the product side, and only one in the reactants side, therefore, we can multiply
Third, look at the hydrogen atoms, you will find
In some cases, I prefer to balance equations using groups (or polyatomic ions) rather than atoms.
You need to make sure that all the elements are equal on both sides.
The first step is write down what you have
N: 1 the side in front of the arrow, 2 on the side after the arrow
H: 5 on the side before the arrow, 8 on the side after the arrow
Now you can see that you need to change the amount of N and H on the side in front of the arrow, to match the amount of N and H after the arrow.
Step two add a number in front of the elements to make both side match:
Step three, check again, make changes if necessary:
N: 2 on both sides
H: 8 on both sides
As you can see, the reaction is now balanced :)