How do you balance #(NH_4)_2CO_3 -> NH_3 + CO_2 + H_2O#?

1 Answer
Mar 15, 2016

Answer:

This equation can be balanced using trial and error method. The most common method of balancing chemical equations.

#(NH_4)_2CO_3 -> 2NH_3 + CO_2 + H_2O#

Explanation:

  1. First is to account the initial number of atoms as reference, both the reactant and the products using the T balance;
  2. Present the elements according to its appearance in the reactant side and copy the same in the product side; though it's no rule on this;
    #Reactant TTProduct#
    #N=2#...........l#N=cancel1 2#
    #H=8#...........l#H=cancel5 8#
    #C=1#............l#C=1#
    #O=3#............l#O=3#
  3. Generally, complex compounds are always considered first and work your way to the least one;
  4. Every change you make with coefficients, make sure to recount the number of atoms of the involve elements and record using your T balance and of course cancelling the previous counts;
  5. In this case, putting 2 as coefficient in the first product of the reaction will suffice the equation.
  6. The balanced equation is
    #(NH_4)_2CO_3->2NH_3+CO_2+H_2O#