# How do you balance S8 + O2 -->SO3?

Oct 18, 2015

${S}_{8}$ + $12 {O}_{2}$ $\rightarrow$ $8 S {O}_{3}$
On the left hand side of the equation, there are 8 (moles of) $S$ atoms. Therefore on the right hand side, there would need to be $8$ (moles of) $S {O}_{3}$ molecules.
If so, on the right hand side now, there would be a total of $24$ (moles of) $O$ atoms. Therefore we need to balance the O atoms on the left hand side giving us $12$ (moles of) ${O}_{2}$ gas.