# How do you balance the following reaction: ?KOH + ?H_3PO_4 -> ?K_3PO_4 + ?H_2O?

Jan 21, 2017

$\text{Garbage in must equal garbage out........}$

#### Explanation:

${H}_{3} P {O}_{4} \left(a q\right) + 3 K O H \left(a q\right) \rightarrow {K}_{3} P {O}_{4} \left(a q\right) + 3 {H}_{2} O \left(l\right)$

This reaction is a bit of an idealization, inasmuch as phosphoric acid behaves as a diprotic acid in water.

A more realistic interpretation would be,

${H}_{3} P {O}_{4} \left(a q\right) + 2 K O H \left(a q\right) \rightarrow {K}_{2} H P {O}_{4} \left(a q\right) + 2 {H}_{2} O \left(l\right)$

In both cases, are mass and charge conserved? If they are not, then you know that the reaction does not reflect reality.