How do you calculate #log_6 3.05 #? Precalculus Exponential and Logistic Modeling Exponential and Logistic Modeling on a Graphing Calculator 1 Answer Shwetank Mauria Jun 9, 2016 #log_6(3.05)=0.6223# Explanation: #log_6(3.05)# = #log3.05/log6# = #0.4843/0.7782# = #0.6223# Answer link Related questions How do I find an appropriate exponential model of given data points on a TI-83? How do I find an exponential model of the form #y = ae^(kt)# on a TI-84? How do I create a logistic model of population growth on a TI-83? What characteristics are identified from the graph of an exponential function? How could the graph of an exponential function be used to determine an #a# value? How do you find the exponential function f(x) = Ca^x whose points given are (-1,3) and (1,-4/3)? How do you find an exponential function given the points are (-1,8) and (1,2)? How do you use the model #y=a * b^x# to find the model for the graph when given the two points,... How do you find the y intercept of an exponential function #q(x) = -7^(x-4) -1#? How do you graph #f(x) = 6^x#? See all questions in Exponential and Logistic Modeling on a Graphing Calculator Impact of this question 1834 views around the world You can reuse this answer Creative Commons License