How do you calculate #log_8 36# with a calculator? Precalculus Properties of Logarithmic Functions Functions with Base b 1 Answer GiĆ³ Aug 17, 2016 I got: #1.7233# changing base of the lg. Explanation: I suppose your calculator has #ln#, so you only need to change base of your log as: #log_8(36)=(ln(36))/(ln(8))=1.7233# Answer link Related questions What is the exponential form of #log_b 35=3#? What is the product rule of logarithms? What is the quotient rule of logarithms? What is the exponent rule of logarithms? What is #log_b 1#? What are some identity rules for logarithms? What is #log_b b^x#? What is the reciprocal of #log_b a#? What does a logarithmic function look like? How do I graph logarithmic functions on a TI-84? See all questions in Functions with Base b Impact of this question 1736 views around the world You can reuse this answer Creative Commons License