How do you calculate #log_9 1.1# with a calculator? Precalculus Properties of Logarithmic Functions Functions with Base b 1 Answer VNVDVI Apr 16, 2018 #log_9 1.1=ln(1.1)/ln(9)approx0.043# Explanation: Recall that #log_ab=log_cb/log_ca=ln(b)/ln(a).# Here, we see #a=9, b=1.1,# so #log_9 1.1=ln(1.1)/ln(9)approx0.043# Answer link Related questions What is the exponential form of #log_b 35=3#? What is the product rule of logarithms? What is the quotient rule of logarithms? What is the exponent rule of logarithms? What is #log_b 1#? What are some identity rules for logarithms? What is #log_b b^x#? What is the reciprocal of #log_b a#? What does a logarithmic function look like? How do I graph logarithmic functions on a TI-84? See all questions in Functions with Base b Impact of this question 1356 views around the world You can reuse this answer Creative Commons License