Question

How do you calculate `sin^-1(-sqrt2/2)`?

Answer 1

225, 315 degrees

It is known that sin 45=`sqrt(2)/2`. Hence, `sin^-1 (-sqrt(2)/2)` would be either in the IIIrd quadrant that is 180+45= 225 degrees or in the IVth quadrant, that is 360-45=315 degrees . These are the two values of the angle between 0 to `2pi`.