Question

How do you calculate the amount of heat needed to increase the temperature of 250g of water from 20 C to 56 C? `C_g = 4.8 J/(C-g)`

Answer 1

`=43.2kJ`

Explanation:

1. Given the data, the formula to use is
   `Q=mCpDeltaT`
   where:
   `m=250g`
   `DeltaT=T_2-T_1=56-20=36^oC`
   `Cp=(4.8J)/(g*C)`
2. This case, just plug in given data to find the heat needed to raise the temperature of the water as provided in the problem.
   `Q=(250cancel(g))((4.8J)/cancel((g*C)))(36^cancel(oC))`
   `Q=43200J`
   `Q=43.2kJ`