# How do you calculate the amount of heat needed to increase the temperature of 250g of water from 20 C to 56 C? C_g = 4.8 J/(C-g)

Dec 26, 2017

$= 43.2 k J$

#### Explanation:

1. Given the data, the formula to use is
$Q = m C p \Delta T$
where:
$m = 250 g$
$\Delta T = {T}_{2} - {T}_{1} = 56 - 20 = {36}^{o} C$
$C p = \frac{4.8 J}{g \cdot C}$
2. This case, just plug in given data to find the heat needed to raise the temperature of the water as provided in the problem.
$Q = \left(250 \cancel{g}\right) \left(\frac{4.8 J}{\cancel{\left(g \cdot C\right)}}\right) \left({36}^{\cancel{o C}}\right)$
$Q = 43200 J$
$Q = 43.2 k J$