# How do you calculate the density of a neutron?

$\text{Density}$ $=$ $\text{Mass"/"Volume}$
So rho=(1.6726231*10^-27* kg)/((4/3)xxpixx(1.113xx10^-15 m )^3
$= 2.90 \times {10}^{17} \cdot k g \cdot {m}^{-} 3$, which is fairly dense.......but then we expected it to be for a fundamental massive particle.