How do you calculate the energy of a photon of radiation with a frequency of $8.5 \times 10^{14}$ $8.5 times 10^14$ $H z$ $Hz$ ?

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Answer 1 · 2017-04-09T01:12:00

$E = 5.6 \cdot 10^{- 19} J$ $E = 5.6*10^-19J$

$E = h f$ $E = hf$

$h$ $h$ = planck's constant = $6.6262 \cdot 10^{- 34} J s$ $6.6262*10^-34 Js$

$f$ $f$ = frequency

$H z = s^{- 1}$ $Hz = s^-1$

$E = (6.6262 \cdot 10^{- 34} J s) (8.5 \cdot 10^{14} s^{- 1})$ $E = (6.6262*10^-34Js)(8.5*10^14s^-1)$

$E = 5.6 \cdot 10^{- 19} J$ $E = 5.6*10^-19J$

How do you calculate the energy of a photon of radiation with a frequency of 8.5 times 10^148.5×10148.5 times 10^14 HzHzHz?