How do you calculate the pH of this solution: #[H^+] = 8.3 xx 10^(-10)# M?

1 Answer

Answer:

#"pH" = 9.08#

Explanation:

The definition of #"pH"# is as follows:

#"pH" -= -log["H"^+]#

Assuming we have #["H"^+] = 8.3 xx 10^-10 "M"# as the only #"H"^(+)# in solution,

#"pH" = -log(8.3xx 10^-10) = 9.08#.

As a rule of thumb, #"pH"# should be treated a dimensionless, meaning that it has no units.