# How do you calculate the pH of this solution: [H^+] = 8.3 xx 10^(-10) M?

Jun 9, 2017

$\text{pH} = 9.08$

#### Explanation:

The definition of $\text{pH}$ is as follows:

"pH" -= -log["H"^+]

Assuming we have ["H"^+] = 8.3 xx 10^-10 "M" as the only ${\text{H}}^{+}$ in solution,

$\text{pH} = - \log \left(8.3 \times {10}^{-} 10\right) = 9.08$.

As a rule of thumb, $\text{pH}$ should be treated a dimensionless, meaning that it has no units.