# How do you change 4^-3 = 1/64 into log form?

${\log}_{4} \left(\frac{1}{64}\right) = - 3$
As ${a}^{n} = b$ in logarithmic form is written as ${\log}_{a} b = n$
Hence, ${4}^{- 3} = \frac{1}{64}$ can be written as ${\log}_{4} \left(\frac{1}{64}\right) = - 3$