How do you change #4^-3 = 1/64# into log form? Precalculus Properties of Logarithmic Functions Logarithm-- Inverse of an Exponential Function 1 Answer Shwetank Mauria Jul 27, 2016 #log_4(1/64)=-3# Explanation: As #a^n=b# in logarithmic form is written as #log_ab=n# Hence, #4^(-3)=1/64# can be written as #log_4(1/64)=-3# Answer link Related questions What is a logarithm? What are common mistakes students make with logarithms? How can a logarithmic equation be solved by graphing? How can I calculate a logarithm without a calculator? How can logarithms be used to solve exponential equations? How do logarithmic functions work? What is the logarithm of a negative number? What is the logarithm of zero? How do I find the logarithm #log_(1/4) 1/64#? How do I find the logarithm #log_(2/3)(8/27)#? See all questions in Logarithm-- Inverse of an Exponential Function Impact of this question 7162 views around the world You can reuse this answer Creative Commons License