How do you change #a^(1/2)b^(4/3)c^(3/4)# into radical form?

1 Answer
May 20, 2017

See a solution process below:

Explanation:

First, we can use this rule of exponents to put the #a# term into radical form:

#x^(1/color(red)(n)) = root(color(red)(n))(x)#

#a^(1/color(red)(2))b^(4/3)c^(3/4) => (root(color(red)(2))(a))b^(4/3)c^(3/4) => (sqrt(a))b^(4/3)c^(3/4)#

Next, we can use this rule of exponents to rewrite the #b# and #c# terms:

#x^(color(red)(a) xx color(blue)(b)) = (x^color(red)(a))^color(blue)(b)#

#(sqrt(a))b^(4/3)c^(3/4) => (sqrt(a))b^(color(red)(4) xx color(blue0)(1/3))c^(color(red)(3) xx color(blue)(1/4)) => sqrt(a)(b^4)^(1/3)(c^3)^(1/4)#

We can again use this rule of exponents to put the #b# and #c# terms in radical form:

#x^(1/color(red)(n)) = root(color(red)(n))(x)#

#sqrt(a)(b^4)^(1/color(red)(3))(c^3)^(1/color(red)(4)) => sqrt(a)root(color(red)(3))(b^4)root(color(red)(4))(c^3)#