How do you combine #10/(b(b+5))+2/b#?

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Answer 1 · 2017-01-22T02:47:16

See the entire solution process below:

First, in order to add fractions they must be over a common denominator, in this case #b(b + 5)#.

We need to multiply the second fraction by the correct form of #1# or #(b + 5)/(b + 5)#

#10/(b(b + 5)) + (2/b xx (b + 5)/(b + 5)) ->#

#10/(b(b + 5)) + (2(b + 5))/(b(b + 5))#

We can now add the two numerators:

#(10 + 2(b + 5))/(b(b + 5))#

We can now expand and simplify the numerator:

#(10 + 2b + 10)/(b(b + 5)) ->#

#(2b + 20)/(b(b + 5))#

And lastly, factor the numerator:

#(2(b + 10))/(b(b + 5))#