How do you combine (2p)/(p-5)-p/(p+6)2pp5pp+6?

1 Answer
May 24, 2018

(p(p+17))/((p-5)(p+6))p(p+17)(p5)(p+6)

Explanation:

As explained below:

(2p)/(p-5) - p/(p+6)2pp5pp+6

Treat this equation as normal fraction:

(2p)/(p-5) - p/(p+6)2pp5pp+6

(2p(p+6) - p(p-5))/((p-5)(p+6))2p(p+6)p(p5)(p5)(p+6)

Open the brackets and we get:

(2p^2+12p-p^2+5p)/((p-5)(p+6))2p2+12pp2+5p(p5)(p+6)

Re-arranging the like terms and we get:

(2p^2-p^2+12p+5p)/((p-5)(p+6))2p2p2+12p+5p(p5)(p+6)

(p^2+17p)/((p-5)(p+6))p2+17p(p5)(p+6)

(p(p+17))/((p-5)(p+6))p(p+17)(p5)(p+6)