How do you combine #(2p)/(p-5)-p/(p+6)#?

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Answer 1 · 2018-05-24T10:41:16

#(p(p+17))/((p-5)(p+6))#

As explained below:

#(2p)/(p-5) - p/(p+6)#

Treat this equation as normal fraction:

#(2p)/(p-5) - p/(p+6)#

#(2p(p+6) - p(p-5))/((p-5)(p+6))#

Open the brackets and we get:

#(2p^2+12p-p^2+5p)/((p-5)(p+6))#

Re-arranging the like terms and we get:

#(2p^2-p^2+12p+5p)/((p-5)(p+6))#

#(p^2+17p)/((p-5)(p+6))#

#(p(p+17))/((p-5)(p+6))#