# How do you combine (2x^2 - 6x - 2) + (x* + 4x) + ( 3x^2 + x + 5)??

Mar 20, 2018

$6 {x}^{2} - x + 3$

#### Explanation:

Combine    (2x^2−6x−2)+(color(red)(x⋅)+4x)+(3x^2+x+5)

NOTE: I think this part $\rightarrow$ color(red)(x⋅) $\leftarrow$is a typo for $\textcolor{red}{{x}^{2}}$

So I will write the problem this way:
Combine    (2x^2−6x−2)+(color(red)(x^2)+4x)+(3x^2+x+5)

1) Clear the parentheses by distributing their coefficients

In this case, the coefficients are $1$s, which are not written because they are understood.
But you can always just pencil them in for yourself, like this:

color(lightgray)1(2x^2−6x−2)+color(lightgray)1(x^2+4x)+color(lightgray)1(3x^2+x+5)

1) Clear the parentheses by distributing the coefficients
After you have distributed, you will get this:

2x^2−6x−2+x^2+4x+3x^2+x+5

2) Group like terms to make it easier to combine them

2x^2+x^2+3x^2    −6x+4x+x      −2+5

3) Combine like terms

$6 {x}^{2} - x + 3$ $\leftarrow$ answer