How do you combine #(2x^2 - 6x - 2) + (x* + 4x) + ( 3x^2 + x + 5)?#?

1 Answer
Mar 20, 2018

#6x^2 - x +3#

Explanation:

Combine    #(2x^2−6x−2)+(color(red)(x⋅)+4x)+(3x^2+x+5)#

NOTE: I think this part #rarr# #color(red)(x⋅)# #larr#is a typo for #color(red)(x^2)#

So I will write the problem this way:
Combine    #(2x^2−6x−2)+(color(red)(x^2)+4x)+(3x^2+x+5)#

1) Clear the parentheses by distributing their coefficients

In this case, the coefficients are #1#s, which are not written because they are understood.
But you can always just pencil them in for yourself, like this:

#color(lightgray)1(2x^2−6x−2)+color(lightgray)1(x^2+4x)+color(lightgray)1(3x^2+x+5)#

1) Clear the parentheses by distributing the coefficients
After you have distributed, you will get this:

#2x^2−6x−2+x^2+4x+3x^2+x+5#

2) Group like terms to make it easier to combine them

#2x^2+x^2+3x^2    −6x+4x+x      −2+5#

3) Combine like terms

#6x^2 - x +3# #larr# answer