# How do you combine (3-r) + (4+5r) + (2r-1)?

Apr 28, 2015

The answer is $6 r + 6$.

$\left(3 - r\right) + \left(4 + 5 r\right) + \left(2 r - 1\right)$

Do what's in each set of parentheses first.

$3 - r + 4 + 5 r + 2 r - 1$ =

Combine like terms and add or subtract from left to right.

$- r + 5 r + 2 r + 3 + 4 - 1$ =

$6 r + 6$