How do you combine #-4/(n^2+6n+5)+3/(n^2+7n+10)#?

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Answer 1 · 2016-07-18T14:20:01

#-1/((n+2)(n+1)#

The Expression#=3/(n^2+7n+10)-4/(n^2+6n+5)#

#=3/((n+5)(n+2))-4/((n+5)(n+1))#

#=(3(n+1)-4(n+2))/((n+5)(n+2)(n+1))#

#=(3n+3-4n-8)/((n+5)(n+2)(n+1))#

#=(-n-5)/((n+5)(n+2)(n+1))#

#=-(n+5)/((n+5)(n+2)(n+1))#

#=-(cancel(n+5))/(cancel((n+5))(n+2)(n+1)#

#=-1/((n+2)(n+1)#