# How do you combine 6/(w(w-2))+3/w?

We have to find the least common factor in the denominator. Since they both have a $w$ term, but the second fraction lacks the $w - 2$ term, we multiply the second fraction by $\frac{w - 2}{w - 2}$.
$\frac{6}{w \left(w - 2\right)} + \frac{3}{w} \setminus \cdot \frac{w - 2}{w - 2} = \frac{6 + 3 w - 6}{w \left(w - 2\right)} = \frac{3 w}{w \left(w - 2\right)} = \frac{3}{w - 2}$