# How do you combine h-3+1/(h+3)?

Apr 22, 2018

$\frac{{h}^{2} - 8}{h + 3}$

#### Explanation:

$\left(\left(h - 3\right) + \frac{1}{h + 3}\right) \left(h + 3\right) = {h}^{2} - 8$

$\frac{{h}^{2} - 8}{h + 3}$

I hope this helps!
There may or may not be another way to do this.