# How do you combine x/(x^2-9) - x/(x^2+6x+9)?

Write the denominators in the factor form $\frac{x}{\left(x - 3\right) \left(x + 3\right)} - \frac{x}{x + 3} ^ 2$
= $\frac{x}{x + 3} \left[\frac{1}{x - 3} - \frac{1}{x + 3}\right]$
=$\frac{6 x}{\left(x - 3\right) {\left(x + 3\right)}^{2}}$