Question

How do you complete a table for the rule `y=1.6x+1` and then graph the line?

Answer 1

See a solution process below:

Explanation:

For a linear equation we only need a table with two points:

Next, we can plot the two points:

graph{(x^2+(y-1)^2-0.075)((x-5)^2+(y-9)^2-0.075)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y - 1.6x - 1)(x^2+(y-1)^2-0.075)((x-5)^2+(y-9)^2-0.075)=0 [-20, 20, -10, 10]}