Question

How do you complete the square for `x^2+6x-7=0`?

Answer 1

`(x+3)^2=16`

Explanation:

The given equation:

`x^2+6x-7=0`

`x^2+2\cdot 3\cdotx-7=0`

`x^2+2\cdot 3\cdot x+3^2-3^3-7=0`

`(x+3)^2-16=0`

`(x+3)^2=16`