# How do you complete the square to solve #-2x^2 - 7x + 4 = 0#?

##### 1 Answer

Jun 1, 2015

NOTE. This method of completing the squares is unadvised when b is an odd number and a is negative. Completing the squares in this case is very challenging and easy to make errors/mistakes.

Solving by the new Transforming method (Google, Yahoo Search) is a lot simpler.

y = -(2x^2 + 7x - 4) = 0 (1)

y' = -(x^2 + 7x - 8) (2) -> a.c = -8 --> factor: (-1, 8) -> sum = b

Two real roots of (2): 1 and -8

Two real roots of (1): 1/2 and -4