How do you condense #1/2log_8(x+5)-3log_8(y)#?

1 Answer
Apr 12, 2016

Answer:

In this problem, the following log rules will be used:

Explanation:

#alogn = logn^a#

#log_na - log_nb = log_n(a/b)#

Since #x^(1/2)# = #sqrt(x)# (by the rule #a^(n/m) = root(n)(a^m)#):

#log_8sqrt(x + 5) - log_8(y^3)#

#log_8((sqrt(x + 5))/(y^3))#

Thus, you have your answer, in simplest form.

Hopefully this helps.